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Sandusky, Iowa
Sandusky is located in Iowa
Sandusky
Sandusky
Sandusky is located in the United States
Sandusky
Sandusky
Coordinates: 40°27′52″N 91°23′13″W / 40.46444°N 91.38694°W / 40.46444; -91.38694
Country United States
StateIowa
CountyLee
TownshipsJackson
Montrose
Area
 • Total2.67 sq mi (6.91 km2)
 • Land1.43 sq mi (3.69 km2)
 • Water1.24 sq mi (3.22 km2)
Elevation543 ft (166 m)
Population
 (2020)
 • Total297
 • Density208.42/sq mi (80.45/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
ZIP Code
52632 (Keokuk)
Area code319
FIPS code19-70545
GNIS feature ID2804144[2]

Sandusky is an unincorporated community and census-designated place (CDP) in Lee County, Iowa, United States. It is in the southeast part of the county, on the west bank of the Mississippi River 4 miles (6 km) north of Keokuk, the county seat, and 6 miles (10 km) south of Montrose.

Sandusky was first listed as a CDP prior to the 2020 census. As of the 2020 census, its population was 297.[3]

Demographics[edit]

Historical population
CensusPop.Note
2020297
U.S. Decennial Census[4]

History[edit]

Founded in the 1800s, Sandusky's population was 85 in 1902,[5] and 60 in 1925.[6]

References[edit]


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