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In functional analysis, a topological vector space (TVS) is said to be quasi-complete or boundedly complete[1] if every closed and bounded subset is complete.[2] This concept is of considerable importance for non-metrizable TVSs.[2]

Properties[edit]

Examples and sufficient conditions[edit]

Every complete TVS is quasi-complete.[7] The product of any collection of quasi-complete spaces is again quasi-complete.[2] The projective limit of any collection of quasi-complete spaces is again quasi-complete.[8] Every semi-reflexive space is quasi-complete.[9]

The quotient of a quasi-complete space by a closed vector subspace may fail to be quasi-complete.

Counter-examples[edit]

There exists an LB-space that is not quasi-complete.[10]

See also[edit]

References[edit]

  1. ^ Wilansky 2013, p. 73.
  2. ^ a b c d e Schaefer & Wolff 1999, p. 27.
  3. ^ Schaefer & Wolff 1999, p. 201.
  4. ^ Schaefer & Wolff 1999, p. 110.
  5. ^ a b Schaefer & Wolff 1999, p. 142.
  6. ^ Trèves 2006, p. 520.
  7. ^ Narici & Beckenstein 2011, pp. 156–175.
  8. ^ Schaefer & Wolff 1999, p. 52.
  9. ^ Schaefer & Wolff 1999, p. 144.
  10. ^ Khaleelulla 1982, pp. 28–63.

Bibliography[edit]