Legality of Cannabis by U.S. Jurisdiction

1990 Iowa gubernatorial election

← 1986 November 8, 1990 1994 →
 
Nominee Terry Branstad Donald Avenson
Party Republican Democratic
Popular vote 591,852 379,372
Percentage 60.6% 38.9%

County results

Branstad:      50-60%      60-70%      70-80%      80-90%

Avenson:      50–60%

Governor before election

Terry Branstad
Republican

Elected Governor

Terry Branstad
Republican

The 1990 Iowa gubernatorial election took place November 8, 1990. Incumbent Republican Governor of Iowa Terry Branstad ran for re-election to a third term as governor. On the Democratic side, state representative Donald Avenson won his party's nomination and both Branstad and Avenson moved on to the general election. Branstad won re-election to a third term as governor, defeating Avenson by a margin of over 20 points.

Democratic primary[edit]

Candidates[edit]

Results[edit]

Democratic primary results[1]
Party Candidate Votes %
Democratic Donald Avenson 79,022 39.45
Democratic Tom Miller 63,364 31.63
Democratic John Crystal 52,170 26.05
Democratic Jo Ann Zimmerman 4,475 2.23
Democratic Darold Powers 1,167 0.58
Democratic Write-ins 107 0.05
Total votes 200,305 100.00

Republican primary[edit]

Candidates[edit]

Results[edit]

Republican primary results[1]
Party Candidate Votes %
Republican Terry Branstad (inc.) 94,253 99.52
Republican Write-ins 453 0.47
Total votes 94,706 100.00

General election[edit]

Results[edit]

Iowa gubernatorial election, 1990[2]
Party Candidate Votes % ±%
Republican Terry Branstad (inc.) 591,852 60.61% +8.70%
Democratic Donald Avenson 379,372 38.85% -9.14%
Socialist Workers Nan Bailey 4,263 0.44%
Write-ins 996 0.10%
Turnout 976,483
Republican hold Swing

See also[edit]

References[edit]

  1. ^ a b "PRIMARY ELECTION : June 5,1990 : OFFICIAL CANVASS SUMMARY" (PDF). Sos.iowa.gov. Retrieved July 5, 2018.
  2. ^ "Archived copy" (PDF). Archived from the original (PDF) on December 4, 2018. Retrieved July 4, 2018.{{cite web}}: CS1 maint: archived copy as title (link)