Legality of Cannabis by U.S. Jurisdiction

1950 Iowa gubernatorial election

← 1948 November 7, 1950 1952 →
 
Nominee William S. Beardsley Lester S. Gillette
Party Republican Democratic
Popular vote 506,642 347,176
Percentage 59.10% 40.50%

County results

Beardsley:      50-60%      60-70%      70-80%

Gillette:      50–60%

Governor before election

William S. Beardsley
Republican

Elected Governor

William S. Beardsley
Republican

The 1950 Iowa gubernatorial election was held on November 7, 1950. Incumbent Republican William S. Beardsley defeated Democratic nominee Lester S. Gillette with 59.10% of the vote.

Primary elections[edit]

Primary elections were held on June 5, 1950.[1]

Democratic primary[edit]

Candidates[edit]

Results[edit]

Democratic primary results[1]
Party Candidate Votes %
Democratic Lester S. Gillette 70,046
Democratic Myron J. Bennett 23,458
Total votes 93,504

Republican primary[edit]

Candidates[edit]

Results[edit]

Republican primary results[1]
Party Candidate Votes %
Republican William S. Beardsley (incumbent) 238,686 100.00
Total votes 238,686 100.00

General election[edit]

Candidates[edit]

Major party candidates

  • William S. Beardsley, Republican
  • Lester S. Gillette, Democratic

Other candidates

  • W. Raymond Picken, Prohibition
  • Howard H. Tyler, Independent

Results[edit]

1950 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican William S. Beardsley (incumbent) 506,642 59.10%
Democratic Lester S. Gillette 347,176 40.50%
Prohibition W. Raymond Picken 2,805 0.33%
Independent Howard H. Tyler 590 0.07%
Majority 159,466
Turnout 857,213
Republican hold Swing

References[edit]