Legality of Cannabis by U.S. Jurisdiction

1889 Iowa gubernatorial election

← 1887 November 5, 1889 1891 →
 
Nominee Horace Boies Joseph Hutchinson
Party Democratic Republican
Popular vote 180,106 173,450
Percentage 49.90% 48.05%

Results by county
Boies:     40–50%      50–60%      60–70%      70–80%
Hutchinson:      40–50%      50–60%      60–70%      70–80%

Governor before election

William Larrabee
Republican

Elected Governor

Horace Boies
Democratic

The 1889 Iowa gubernatorial election was held on November 5, 1889. Democratic nominee Horace Boies defeated Republican nominee Joseph Hutchinson with 49.90% of the vote.

General election[edit]

Candidates[edit]

Major party candidates

  • Horace Boies, Democratic
  • Joseph Hutchinson, Republican

Other candidates

  • S. B. Downing, Union Labor
  • Malcolm Smith, Prohibition

Results[edit]

1889 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Democratic Horace Boies 180,106 49.90%
Republican Joseph Hutchinson 173,450 48.05%
Labor S. B. Downing 5,773 1.60%
Prohibition Malcolm Smith 1,362 0.38%
Majority 6,656
Turnout
Democratic gain from Republican Swing

References[edit]

  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 12, 2020.