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| Elections in Delaware |
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The 1872 United States presidential election in Delaware took place on November 5, 1872, as part of the 1872 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Delaware voted for the Republican candidate, Ulysses S. Grant, over Liberal Republican candidate Horace Greeley. Grant won Delaware by a narrow margin of 4.24%, making him the first Republican to win the state in a presidential election. It would not be carried by another Republican presidential candidate until 1896.
Results[edit]
| 1872 United States presidential election in Delaware[1][2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Ulysses S. Grant of Illinois | Henry Wilson of Massachusetts | 11,129 | 51.00% | 3 | 100.00% | ||
| Liberal Republican | Horace Greely of New York | Benjamin Gratz Brown of Missouri | 10,205 | 46.76% | 0 | 0.00% | ||
| Straight-Out Democratic | Charles O'Conor | John Quincy Adams II | 488 | 2.24% | 0 | 0.00% | ||
| Total | 21,822 | 100.00% | 3 | 100.00% | ||||
See also[edit]
References[edit]
- ^ "1872 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved March 6, 2018.
- ^ "1872 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.
